Which equation of a line passes through the points (3, −1) and (6, 1)?Y = 2/3x - 3Y = - 2/3x + 5Y = - 2/3x + 10Y = 3/2x - 8

Answer:Y = 2/3x - 3Step-by-step explanation:Recall the general equation for a straight line is y = mx + bwhere m is the gradient and b is the y-interceptgiven 2 points whose coordinates are (x1, y1) and (x2, y2), m can be found with the following formula:m = [tex]\frac{y1-y2}{x1-x2}[/tex]in this case, x1 = 3, y1 = -1, x2 = 6, y2=1applying these values to the formula for m will give m =  (-1 -1) / (3-6) = 2/3We can see immediately that only the first (top-most) answer has this value for m and we can guess that this is probably the answer.But we can still check to confirm:If we substitute this back into the general equation, we get:y = (2/3)x + bIn order to find the value for b, we substitute any one of the 2 given points back into this equation. Lets choose (6,1)1 = (2/3)(6) + b1 = 4 + bb = -3Confirm  Y = 2/3x - 3 is the answer.