You are competing in a race. The table shows the times from last year's race you want your time to be last year's median time with an absolutedeviation of at most 5 minutes. Complete the inequality to represent the time in minutes) you hope to achieve
Accepted Solution
A:
Answer:[tex]27\leq x \leq37[/tex]Step-by-step explanation:Let's arrange the numbers from least to greatest:20, 25, 27, 28, 31, 32, 32, 38, 40, 40, 42, 48The median is the "middle" number when arranged from least to greatest.There are 12 numbers, so the middle number would be "average" of 6th and 7th terms.6th term = 327th term = 32Average = (32+32)/2 = 32Hence, median = 32Absolute deviation of 5 minutes means 5 minutes less or greater than the median, 32.So, 32 - 5 = 27 & 32 + 5 = 37Hence [tex]27\leq x \leq37[/tex]